Skip to content

Make any .NET object a fluent interface regardless if you have the source code or not!

License

Notifications You must be signed in to change notification settings

smatsson/Chainly

Folders and files

NameName
Last commit message
Last commit date

Latest commit

 

History

15 Commits
 
 
 
 
 
 
 
 
 
 
 
 

Repository files navigation

Chainly

Make any .NET object a fluent interface regardless if you have the source code or not!

NuGet

PM> Install-Package Chainly

Reflection.Emit method

Example

Given a class Asdf we define an interface IAsdfChain. We then run the Chain extension on the Asdf instance and voila! Fluent interface! :)

var myString = new Asdf("This is my string!")
				.Chain<IAsdfChain>()
				.SomeMethod()
				.ParameterMethod("A", 123)
				.Value() // Call .Value() to get the unchained Asdf instance
				.GetMyString();
// myString == "This is my string!"

public class Asdf
{
	private readonly string _myString;

	public int SomeMethodCount { get; set; }
	public int ParameterMethodWithTwoParametersCount { get; set; }

	public Asdf(string myString)
	{
		_myString = myString;
	}

	public void SomeMethod()
	{
		SomeMethodCount++;
	}

	public void ParameterMethod(string value, int otherValue)
	{
		ParameterMethodWithTwoParametersCount++;
	}

	public string GetMyString()
	{
		return _myString;
	}
}

// Only methods defined in this interface will be made fluent. Other methods will be left alone.
public interface IAsdfChain
{
	IAsdfChain SomeMethod();
	IAsdfChain ParameterMethod(string value, int value2);
	// Value is a special method, returning the original unchained object.
	Asdf Value();
}

Of course it also works with built in classes!

var buffer = new char[2];
var asdfUpper = "asdf".Chain<IChainString>().CopyTo(0, buffer, 0, 2).Value().ToUpper();
// buffer == ['a', 's']
// asdfUpper = ASDF

var elapsed = StopWatch.StartNew().Chain<IStopWatchChain>().Stop().Value().Elapsed;

public interface IChainString
{
	IChainString CopyTo(int sourceIndex, char[] destination, int destinationIndex, int count);
	string Value();
}

public interface IStopWatchChain
{
	IStopWatchChain Stop();
	Stopwatch Value();
}

What are the steps to make an object fluent?

  • Create an interface. You can call it anything you'd like but it must be public.
  • Add each void method you want to make fluent to the interface and use the interface as return type (not all void methods are required, only the ones you wish to make fluent).
  • Add a Value method with the object type as return value.
  • Run Chain<{interfacename}> on the object to make it fluent.

Example

public interface IMyInterface
{
	IMyInterface SomeVoidMethod(string param1, int param2);
	object Value();
}

objectWithSomeVoidMethod = objectWithSomeVoidMethod
							.Chain<IMyInterface>
							.SomeVoidMethod("A", 1)
							.SomeVoidMethod("B", 2)
							.Value();

Action based method

Summary

The action based method allows chaining for any type without the need for an interface.

Example

var model = new Asdf("a");

var myString = model.Chain()
	.Do(m => m.ParameterMethod("b"))
	.Do(m => m.ParameterMethod("c"))
	.Do(m => m.ParameterMethod("d", 1))
	.Value()
	.GetMyString();

Overloaded Operator Example

It's also possible to use + instead of .Do().

var model = new Asdf("a");

var myString = (model.Chain()
				+ (m => m.ParameterMethod("b"))
				+ (m => m.ParameterMethod("c"))
				+ (m => m.ParameterMethod("d", 1)))
	.Value()
	.GetMyString();

Project structure

Chainly.Dotnet.sln - .NET core project supporting multiple frameworks Chainly.net452.sln - Old .NET 4.5.2 solution kept for compatibility

License

This project is licensed under the MIT license, see LICENSE.

About

Make any .NET object a fluent interface regardless if you have the source code or not!

Topics

Resources

License

Stars

Watchers

Forks

Packages

No packages published