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The important point then is that: not every context-free language is determinstic
To see this, consider the language ${x^ny^n ;\mid; n \geq 0} \cup {x^ny^{2n} ;\mid; n \geq 0}$ We can easily show that this context-free by giving its CFG. However, we will show that it is not deterministic context-free.
The text was updated successfully, but these errors were encountered:
http://www.cs.nuim.ie/~jpower/Courses/Previous/parsing/node38.html
The important point then is that: not every context-free language is determinstic${x^ny^n ;\mid; n \geq 0} \cup {x^ny^{2n} ;\mid; n \geq 0}$ We can easily show that this context-free by giving its CFG. However, we will show that it is not deterministic context-free.
To see this, consider the language
The text was updated successfully, but these errors were encountered: