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Type inference cannot assign the same string to two sorts #21

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wisnesky opened this issue Apr 15, 2019 · 0 comments

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wisnesky commented Apr 15, 2019

So e.name = e is not allowed even if e:Employee and name:Employee->String and e:String can be expressed. To work around, write e.name = e@String.

wisnesky added the enhancement label

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